A woman has polydactyly. Her partner does not have polydactyly. There is a 50% chance that their children...

Question

1. A woman has polydactyly. Her partner does not have polydactyly. There is a 50% chance that their children will have polydactyly.
Draw a genetic diagram to explain why.
2. The diagram shows the inheritance of cystic fibrosis in one family.
Person A is pregnant with her second child.
What is the probability that her second child will have cystic fibrosis? _______

SnapAndSolve AI · Accepted Answer

1. Polydactyly is typically caused by a dominant allele. Let's use 'P' for the polydactyly allele and 'p' for the normal allele. The woman with polydactyly could be heterozygous (Pp), and her partner is homozygous recessive (pp). The possible combinations for their children are:

Pp (polydactyly)
pp (normal)

Thus, there is a 50% chance for each child to have polydactyly.

2. Cystic fibrosis is a recessive disorder. If Person A is a carrier (heterozygous, Cc) and her partner is also a carrier (Cc), the possible combinations for their children are:

CC (normal)
Cc (carrier)
Cc (carrier)
cc (cystic fibrosis)

There is a 25% probability that her second child will have cystic fibrosis.

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A woman has polydactyly. Her partner does not have polydactyly. There is a 50% chance that their children...

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