Determine the percentage composition of each element in table sugar, C12H22O11.
Determine the percentage composition of each element in table sugar, C12H22O11.
Solution:
(12(12.011 g/mole C) / 342.297 g/mole C12H22O11) x 100 = 42.107% C
(22(1.008 g/mole H) / 342.297 g/mole C12H22O11) x 100 = 6.479% H
(11(15.999 g/mole O) / 342.297 g/mole C12H22O11) x 100 = 51.414% O
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