How many molecules of oxygen are in 1.00 kg of oxygen?
2) How many formula units are in 198 g cesium sulfate?
3) How many grams are in 1.00 atom zinc?
4) How many grams are in 2.94 x 10^24 formula units of copper (II) sulfate pentahydrate?
1) To find the number of molecules of oxygen in 1.00 kg of oxygen, use the molar mass of O2 (32.00 g/mol) and Avogadro's number (6.022 x 1023 molecules/mol):
1.00 kg = 1000 g
Number of moles of O2 = 1000 g / 32.00 g/mol = 31.25 mol
Number of molecules = 31.25 mol x 6.022 x 1023 molecules/mol = 1.88 x 1025 molecules
2) To find the number of formula units in 198 g of cesium sulfate (Cs2SO4), use its molar mass (361.87 g/mol):
Number of moles = 198 g / 361.87 g/mol = 0.547 mol
Number of formula units = 0.547 mol x 6.022 x 1023 formula units/mol = 3.30 x 1023 formula units
3) To find the grams in 1.00 atom of zinc, use the molar mass of zinc (65.38 g/mol):
1 atom = 1 / 6.022 x 1023 mol
Mass = (1 / 6.022 x 1023) mol x 65.38 g/mol = 1.09 x 10-22 g
4) To find the grams in 2.94 x 1024 formula units of copper (II) sulfate pentahydrate (CuSO4·5H2O), use its molar mass (249.68 g/mol):
Number of moles = 2.94 x 1024 formula units / 6.022 x 1023 formula units/mol = 4.88 mol
Mass = 4.88 mol x 249.68 g/mol = 1218.3 g
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