Web Analytics

Questions › Math

Math Asked by a SnapAndSolve user · about 2 hours ago

How many molecules of oxygen are in 1.00 kg of oxygen?

1) How many molecules of oxygen are in 1.00 kg of oxygen?
2) How many formula units are in 198 g cesium sulfate?
3) How many grams are in 1.00 atom zinc?
4) How many grams are in 2.94 x 10^24 formula units of copper (II) sulfate pentahydrate?

Answer

  1. 1) To find the number of molecules of oxygen in 1.00 kg of oxygen, use the molar mass of O2 (32.00 g/mol) and Avogadro's number (6.022 x 1023 molecules/mol):

    1.00 kg = 1000 g

    Number of moles of O2 = 1000 g / 32.00 g/mol = 31.25 mol

    Number of molecules = 31.25 mol x 6.022 x 1023 molecules/mol = 1.88 x 1025 molecules

  2. 2) To find the number of formula units in 198 g of cesium sulfate (Cs2SO4), use its molar mass (361.87 g/mol):

    Number of moles = 198 g / 361.87 g/mol = 0.547 mol

    Number of formula units = 0.547 mol x 6.022 x 1023 formula units/mol = 3.30 x 1023 formula units

  3. 3) To find the grams in 1.00 atom of zinc, use the molar mass of zinc (65.38 g/mol):

    1 atom = 1 / 6.022 x 1023 mol

    Mass = (1 / 6.022 x 1023) mol x 65.38 g/mol = 1.09 x 10-22 g

  4. 4) To find the grams in 2.94 x 1024 formula units of copper (II) sulfate pentahydrate (CuSO4·5H2O), use its molar mass (249.68 g/mol):

    Number of moles = 2.94 x 1024 formula units / 6.022 x 1023 formula units/mol = 4.88 mol

    Mass = 4.88 mol x 249.68 g/mol = 1218.3 g

Have a similar question?

Snap a photo of your homework and get a step-by-step answer in seconds. You can ask follow-up questions until it makes sense.

Solve my question free Math help Find a math tutor

More math questions