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Fermentation is a chemical process used to make alcoholic beverages like beer and wine, where sugar...

4. Fermentation is a chemical process used to make alcoholic beverages like beer and wine, where sugar (glucose) is turned into alcohol (ethanol) and carbon dioxide:
C6H12O6 (aq) -> 2 C2H5OH (aq) + 2 CO2 (g)
(glucose) (ethanol)
How many grams of ethanol will be made if you fermented 695 grams glucose? Molar mass of glucose is 180.18 g/mol. Molar mass of ethanol is 46.08 g/mol.
5. If you leave wine standing open to the air, oxygen will oxidize ethanol (the alcohol) to make acetic acid (which is vinegar):
C2H5OH (aq) + O2 (g) -> HC2H3O2 (aq) + H2O (aq)
(ethanol) (acetic acid)
How many grams of acetic acid will you make if 5.00 grams of oxygen gas reacted?
6. Consider again the reaction that takes place when you burn propane gas:
C3H8 (g) + 5 O2 (g) -> 3 CO2 (g) + 4 H2O (g) + Δ
a) Is this reaction endothermic or exothermic?
b) What would happen to the rate of reaction if there were a decrease in the concentration of oxygen?
c) What would happen to the rate of reaction if there were an increase in the concentration of propane?

Answer

  1. First, calculate the moles of glucose:
    Moles of glucose = 695 g / 180.18 g/mol = 3.86 mol
    From the balanced equation, 1 mol of glucose produces 2 mol of ethanol.
    Moles of ethanol = 3.86 mol * 2 = 7.72 mol
    Mass of ethanol = 7.72 mol * 46.08 g/mol = 355.13 g
    355.13 grams of ethanol will be made.

  2. First, calculate the moles of oxygen:
    Moles of O2 = 5.00 g / 32.00 g/mol = 0.15625 mol
    From the balanced equation, 1 mol of O2 produces 1 mol of acetic acid.
    Moles of acetic acid = 0.15625 mol
    Mass of acetic acid = 0.15625 mol * 60.05 g/mol = 9.38 g
    9.38 grams of acetic acid will be made.

    1. Exothermic (the reaction releases heat).

    2. Decrease (a decrease in the concentration of oxygen would decrease the rate of reaction).

    3. Increase (an increase in the concentration of propane would increase the rate of reaction).

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